# Run this cell to set up packages for lecture.
from lec23_imports import *
I am out of town on Friday, so instead of holding lecture as usual, I am posting a recording of Lecture 24 for you to watch asynchronously. Please do not come to class on Friday!
At a high level, the second half of this class has been about statistical inference – using a sample to draw conclusions about the population.
hybrid = bpd.read_csv('data/hybrid.csv')
hybrid
vehicle | year | price | acceleration | mpg | class | |
---|---|---|---|---|---|---|
0 | Prius (1st Gen) | 1997 | 24509.74 | 7.46 | 41.26 | Compact |
1 | Tino | 2000 | 35354.97 | 8.20 | 54.10 | Compact |
2 | Prius (2nd Gen) | 2000 | 26832.25 | 7.97 | 45.23 | Compact |
... | ... | ... | ... | ... | ... | ... |
150 | C-Max Energi Plug-in | 2013 | 32950.00 | 11.76 | 43.00 | Midsize |
151 | Fusion Energi Plug-in | 2013 | 38700.00 | 11.76 | 43.00 | Midsize |
152 | Chevrolet Volt | 2013 | 39145.00 | 11.11 | 37.00 | Compact |
153 rows × 6 columns
'price'
vs. 'acceleration'
¶Is there an association between these two variables? If so, what kind?
(Note: When looking at a scatter plot, we often describe it in the form "$y$ vs. $x$.")
hybrid.plot(kind='scatter', x='acceleration', y='price');
Acceleration here is measured in kilometers per hour per second – this means that larger accelerations correspond to quicker cars!
'price'
vs. 'mpg'
¶Is there an association between these two variables? If so, what kind?
hybrid.plot(kind='scatter', x='mpg', y='price');
Just for fun, we can look at an interactive version of the previous plot. Hover over a point to see the name of the corresponding car.
px.scatter(hybrid.to_df(), x='mpg', y='price', hover_name='vehicle')
Do you recognize any of the most expensive or most efficient cars? (If not, Google "ActiveHybrid 7i", "Panamera S", and "Prius.")
Consider the following few scatter plots.
show_scatter_grid()
Observation: When $r = 1$, the scatter plot of $x$ and $y$ is a line with a positive slope, and when $r = -1$, the scatter plot of $x$ and $y$ is a line with a negative slope. When $r = 0$, the scatter plot of $x$ and $y$ is a patternless cloud of points.
To see more example scatter plots with different values of $r$, play with the widget that appears below.
widgets.interact(r_scatter, r=(-1, 1, 0.05));
interactive(children=(FloatSlider(value=0.0, description='r', max=1.0, min=-1.0, step=0.05), Output()), _dom_c…
Let's now compute the value of $r$ for the two scatter plots ('price'
vs. 'acceleration'
and 'price'
vs. 'mpg'
) we saw earlier.
def standard_units(col):
return (col - col.mean()) / np.std(col)
Let's define a function that calculates the correlation, $r$, between two columns in a DataFrame.
def calculate_r(df, x, y):
'''Returns the average value of the product of x and y,
when both are measured in standard units.'''
x_su = standard_units(df.get(x))
y_su = standard_units(df.get(y))
return (x_su * y_su).mean()
'price'
vs. 'acceleration'
¶Let's calculate $r$ for 'acceleration'
and 'price'
.
hybrid.plot(kind='scatter', x='acceleration', y='price');
calculate_r(hybrid, 'acceleration', 'price')
0.6955778996913978
Observation: $r$ is positive, and the association between 'acceleration'
and 'price'
is positive.
'price'
vs. 'mpg'
¶Let's now calculate $r$ for 'mpg'
and 'price'
.
hybrid.plot(kind='scatter', x='mpg', y='price');
calculate_r(hybrid, 'mpg', 'price')
-0.5318263633683786
Observation: $r$ is negative, and the association between 'mpg'
and 'price'
is negative.
Also, $r$ here is closer to 0 than it was on the previous slide – that is, the magnitude (absolute value) of $r$ is less than in the previous scatter plot – and the points in this scatter plot look less like a straight line than they did in the previous scatter plot.
A linear transformation to a variable results from adding, subtracting, multiplying, and/or dividing each value by a constant. For example, the conversion from degrees Celsius to degrees Fahrenheit is a linear transformation:
$$\text{temperature (Fahrenheit)} = \frac{9}{5} \times \text{temperature (Celsius)} + 32$$
hybrid.plot(kind='scatter', x='mpg', y='price', title='price (dollars) vs. mpg');
hybrid.assign(
price_yen=hybrid.get('price') * 149.99, # The current USD to Japanese Yen exchange rate.
kpg=hybrid.get('mpg') * 1.6 # 1 mile is 1.6 kilometers.
).plot(kind='scatter', x='kpg', y='price_yen', title='price (yen) vs. kpg');
To better understand why $r$ is the average value of the product of $x$ and $y$, when both are measured in standard units, let's convert the 'acceleration'
, 'mpg'
, and 'price'
columns to standard units, redraw the same scatter plots we saw earlier, and explore what we can learn from the product of $x$ and $y$ in standard units.
def standardize(df):
"""Return a DataFrame in which all columns of df are converted to standard units."""
df_su = bpd.DataFrame()
for column in df.columns:
# This uses syntax that is out of scope; don't worry about how it works.
df_su = df_su.assign(**{column + ' (su)': standard_units(df.get(column))})
return df_su
hybrid_su = standardize(hybrid.get(['acceleration', 'mpg', 'price']))
hybrid_su
acceleration (su) | mpg (su) | price (su) | |
---|---|---|---|
0 | -1.54 | 0.59 | -6.94e-01 |
1 | -1.28 | 1.76 | -1.86e-01 |
2 | -1.36 | 0.95 | -5.85e-01 |
... | ... | ... | ... |
150 | -0.07 | 0.75 | -2.98e-01 |
151 | -0.07 | 0.75 | -2.90e-02 |
152 | -0.29 | 0.20 | -8.17e-03 |
153 rows × 3 columns
'price'
vs. 'acceleration'
¶Here, 'acceleration'
and 'price'
are both measured in standard units. Note that the shape of the scatter plot is the same as before; it's just that the axes are on a different scale.
hybrid_su.plot(kind='scatter', x='acceleration (su)', y='price (su)')
plt.axvline(0, color='black')
plt.axhline(0, color='black');
'acceleration'
($x$) and 'price'
($y$) is positive ↗️. Most data points fall in either the lower left quadrant (where $x_{i \: \text{(su)}}$ and $y_{i \: \text{(su)}}$ are both negative) or the upper right quadrant (where $x_{i \: \text{(su)}}$ and $y_{i \: \text{(su)}}$ are both positive).calculate_r(hybrid, 'acceleration', 'price')
0.6955778996913978
'price'
vs. 'mpg'
¶Here, 'mpg'
and 'price'
are both measured in standard units. Again, note that the shape of the scatter plot is the same as before.
hybrid_su.plot(kind='scatter', x='mpg (su)', y='price (su)')
plt.axvline(0, color='black');
plt.axhline(0, color='black');
'mpg'
($x$) and 'price'
($y$) is negative ↘️. Most data points fall in the upper left or lower right quadrants.calculate_r(hybrid, 'mpg', 'price')
-0.5318263633683786
# Once again, run this cell and play with the slider that appears!
widgets.interact(r_scatter, r=(-1, 1, 0.05));
interactive(children=(FloatSlider(value=0.0, description='r', max=1.0, min=-1.0, step=0.05), Output()), _dom_c…
Which of the following does the scatter plot below show?
x2 = bpd.DataFrame().assign(
x=np.arange(-6, 6.1, 0.5),
y=np.arange(-6, 6.1, 0.5) ** 2
)
x2.plot(kind='scatter', x='x', y='y');
The data below was collected in the late 1800s by Francis Galton.
galton = bpd.read_csv('data/galton.csv')
galton
family | father | mother | midparentHeight | children | childNum | gender | childHeight | |
---|---|---|---|---|---|---|---|---|
0 | 1 | 78.5 | 67.0 | 75.43 | 4 | 1 | male | 73.2 |
1 | 1 | 78.5 | 67.0 | 75.43 | 4 | 2 | female | 69.2 |
2 | 1 | 78.5 | 67.0 | 75.43 | 4 | 3 | female | 69.0 |
... | ... | ... | ... | ... | ... | ... | ... | ... |
931 | 203 | 62.0 | 66.0 | 66.64 | 3 | 3 | female | 61.0 |
932 | 204 | 62.5 | 63.0 | 65.27 | 2 | 1 | male | 66.5 |
933 | 204 | 62.5 | 63.0 | 65.27 | 2 | 2 | female | 57.0 |
934 rows × 8 columns
Let's focus on the relationship between mothers' heights and their adult sons' heights.
male_children = galton[galton.get('gender') == 'male'].reset_index()
mom_son = bpd.DataFrame().assign(mom=male_children.get('mother'), son=male_children.get('childHeight'))
mom_son
mom | son | |
---|---|---|
0 | 67.0 | 73.2 |
1 | 66.5 | 73.5 |
2 | 66.5 | 72.5 |
... | ... | ... |
478 | 60.0 | 66.0 |
479 | 66.0 | 64.0 |
480 | 63.0 | 66.5 |
481 rows × 2 columns
mom_son.plot(kind='scatter', x='mom', y='son');
The scatter plot demonstrates a positive linear association between mothers' heights and their adult sons' heights, so $r$ should be positive.
r_mom_son = calculate_r(mom_son, 'mom', 'son')
r_mom_son
0.3230049836849053
'mom'
and 'son'
are measured in standard units, not inches.mom_son_su = standardize(mom_son)
def constant_prediction(prediction):
mom_son_su.plot(kind='scatter', x='mom (su)', y='son (su)', title=f'Predicting a height of {prediction} SUs for all sons', figsize=(10, 5));
plt.axhline(prediction, color='orange', lw=4);
plt.xlim(-3, 3)
plt.show()
prediction = widgets.FloatSlider(value=-3, min=-3,max=3,step=0.5, description='prediction')
ui = widgets.HBox([prediction])
out = widgets.interactive_output(constant_prediction, {'prediction': prediction})
display(ui, out)
HBox(children=(FloatSlider(value=-3.0, description='prediction', max=3.0, min=-3.0, step=0.5),))
Output()
mom_son_su.plot(kind='scatter', x='mom (su)', y='son (su)', title='A good prediction is the mean height of sons (0 SUs)', figsize=(10, 5));
plt.axhline(0, color='orange', lw=4);
plt.xlim(-3, 3);
def linear_prediction(slope):
x = np.linspace(-3, 3)
y = x * slope
mom_son_su.plot(kind='scatter', x='mom (su)', y='son (su)', figsize=(10, 5));
plt.plot(x, y, color='orange', lw=4)
plt.xlim(-3, 3)
plt.title(r"Predicting sons' heights using $\mathrm{son}_{\mathrm{(su)}}$ = " + str(np.round(slope, 2)) + r"$ \cdot \mathrm{mother}_{\mathrm{(su)}}$")
plt.show()
slope = widgets.FloatSlider(value=0, min=-1,max=1,step=1/6, description='slope')
ui = widgets.HBox([slope])
out = widgets.interactive_output(linear_prediction, {'slope': slope})
display(ui, out)
HBox(children=(FloatSlider(value=0.0, description='slope', max=1.0, min=-1.0, step=0.16666666666666666),))
Output()
x = np.linspace(-3, 3)
y = x * r_mom_son
mom_son_su.plot(kind='scatter', x='mom (su)', y='son (su)', title=r'A good line goes through the origin and has slope $r$', figsize=(10, 5));
plt.plot(x, y, color='orange', label='regression line', lw=4)
plt.xlim(-3, 3)
plt.legend();
More on regression, including: